Between which two consecutive whole numbers does [tex]$\sqrt{28}$[/tex] lie?

Fill out the sentence below to justify your answer and use your mouse to drag [tex]$\sqrt{28}$[/tex] to an approximately correct location on the number line.

Since [tex]$\sqrt{\square}=\square$[/tex] and [tex][tex]$\sqrt{\square}=\square$[/tex][/tex], it is known that [tex]$\sqrt{28}$[/tex] is between [tex]$\square$[/tex] and [tex][tex]$\square$[/tex][/tex].



Answer :

To determine between which two consecutive whole numbers the square root of 28 lies, we need to follow these steps:

1. Calculate the square root: First, we find the square root of 28. This is represented mathematically as [tex]\( \sqrt{28} \)[/tex].
2. Determine the approximate value: After calculating, we find that [tex]\( \sqrt{28} \approx 5.291502622129181 \)[/tex].
3. Identify the whole number bounds: Next, we need to identify the two consecutive whole numbers between which this value lies. To do this, we look for the greatest whole number less than [tex]\( \sqrt{28} \)[/tex] and the smallest whole number greater than [tex]\( \sqrt{28} \)[/tex].

Following these steps:
- [tex]\( \sqrt{28} \)[/tex] is approximately 5.291502622129181.
- The greatest whole number less than 5.291502622129181 is 5.
- The smallest whole number greater than 5.291502622129181 is 6.

Therefore, we can conclude that:
[tex]$ \sqrt{5^2} = \sqrt{25} = 5 $[/tex]
and
[tex]$ \sqrt{6^2} = \sqrt{36} = 6 $[/tex]

Thus, [tex]\( \sqrt{28} \)[/tex] is between 5 and 6.

To fill out the sentence:

Since [tex]\( \sqrt{25} = 5 \)[/tex] and [tex]\( \sqrt{36} = 6 \)[/tex], it is known that [tex]\( \sqrt{28} \)[/tex] is between 5 and 6.