Answer :
To determine between which two consecutive whole numbers the square root of 28 lies, we need to follow these steps:
1. Calculate the square root: First, we find the square root of 28. This is represented mathematically as [tex]\( \sqrt{28} \)[/tex].
2. Determine the approximate value: After calculating, we find that [tex]\( \sqrt{28} \approx 5.291502622129181 \)[/tex].
3. Identify the whole number bounds: Next, we need to identify the two consecutive whole numbers between which this value lies. To do this, we look for the greatest whole number less than [tex]\( \sqrt{28} \)[/tex] and the smallest whole number greater than [tex]\( \sqrt{28} \)[/tex].
Following these steps:
- [tex]\( \sqrt{28} \)[/tex] is approximately 5.291502622129181.
- The greatest whole number less than 5.291502622129181 is 5.
- The smallest whole number greater than 5.291502622129181 is 6.
Therefore, we can conclude that:
[tex]$ \sqrt{5^2} = \sqrt{25} = 5 $[/tex]
and
[tex]$ \sqrt{6^2} = \sqrt{36} = 6 $[/tex]
Thus, [tex]\( \sqrt{28} \)[/tex] is between 5 and 6.
To fill out the sentence:
Since [tex]\( \sqrt{25} = 5 \)[/tex] and [tex]\( \sqrt{36} = 6 \)[/tex], it is known that [tex]\( \sqrt{28} \)[/tex] is between 5 and 6.
1. Calculate the square root: First, we find the square root of 28. This is represented mathematically as [tex]\( \sqrt{28} \)[/tex].
2. Determine the approximate value: After calculating, we find that [tex]\( \sqrt{28} \approx 5.291502622129181 \)[/tex].
3. Identify the whole number bounds: Next, we need to identify the two consecutive whole numbers between which this value lies. To do this, we look for the greatest whole number less than [tex]\( \sqrt{28} \)[/tex] and the smallest whole number greater than [tex]\( \sqrt{28} \)[/tex].
Following these steps:
- [tex]\( \sqrt{28} \)[/tex] is approximately 5.291502622129181.
- The greatest whole number less than 5.291502622129181 is 5.
- The smallest whole number greater than 5.291502622129181 is 6.
Therefore, we can conclude that:
[tex]$ \sqrt{5^2} = \sqrt{25} = 5 $[/tex]
and
[tex]$ \sqrt{6^2} = \sqrt{36} = 6 $[/tex]
Thus, [tex]\( \sqrt{28} \)[/tex] is between 5 and 6.
To fill out the sentence:
Since [tex]\( \sqrt{25} = 5 \)[/tex] and [tex]\( \sqrt{36} = 6 \)[/tex], it is known that [tex]\( \sqrt{28} \)[/tex] is between 5 and 6.