Determine whether the compound condition is True or False.

1. [tex]2 \ \textless \ 3[/tex] and [tex]5 \ \textless \ 1[/tex] [ ]
2. [tex]3 \ \textless \ 3[/tex] or [tex]1 \leq 1[/tex] [ ]
3. not [tex](2 == 3)[/tex] [ ]



Answer :

To determine whether each compound condition is True or False:

1. First Compound Condition:
[tex]\(2 < 3 \text{ and } 5 < 1\)[/tex]

- [tex]\(2 < 3\)[/tex] is True because 2 is indeed less than 3.
- [tex]\(5 < 1\)[/tex] is False because 5 is not less than 1.

The compound condition uses "and," which means both parts must be True for the entire expression to be True. Since one part is False, the entire condition is False.

Therefore, the first condition is False.

2. Second Compound Condition:
[tex]\(3 < 3 \text{ or } 1 \leq 1\)[/tex]

- [tex]\(3 < 3\)[/tex] is False because 3 is not less than 3.
- [tex]\(1 \leq 1\)[/tex] is True because 1 is equal to 1.

The compound condition uses "or," which means only one part needs to be True for the entire expression to be True. Since one part is True, the entire condition is True.

Therefore, the second condition is True.

3. Third Compound Condition:
[tex]\(\text{not } (2 == 3)\)[/tex]

- [tex]\(2 == 3\)[/tex] is False because 2 is not equal to 3.
- The "not" operator negates the condition, meaning it takes the opposite value of the condition it is applied to. Since [tex]\(2 == 3\)[/tex] is False, "not False" is True.

Therefore, the third condition is True.

Combining these evaluations, the results for the conditions are:

1. False
2. True
3. True

In conclusion, the determined outcomes for the conditions are:

[tex]\[ (False, True, True) \][/tex]