If the measure of angle 2 is [tex]$92^{\circ}$[/tex] and the measure of angle 4 is [tex]\left(\frac{1}{2} x\right)^{\circ}[/tex], what is the value of [tex]$x$[/tex]?

A. 46
B. 92



Answer :

Let the measure of angle 2 be given as [tex]\( 92^\circ \)[/tex].

The measure of angle 4 is given as [tex]\( \left(\frac{1}{2} x\right)^\circ \)[/tex].

We are to find the value of [tex]\( x \)[/tex] such that angle 2 equals angle 4.

Set up an equation to represent this relationship:

[tex]\[ 92 = \left(\frac{1}{2} x\right) \][/tex]

To solve for [tex]\( x \)[/tex], we need to isolate [tex]\( x \)[/tex]. We do this by eliminating the fraction [tex]\(\frac{1}{2}\)[/tex] on the right-hand side. Multiply both sides of the equation by 2:

[tex]\[ 2 \cdot 92 = 2 \cdot \left(\frac{1}{2} x\right) \][/tex]

This simplifies to:

[tex]\[ 184 = x \][/tex]

Therefore, the value of [tex]\( x \)[/tex] is:

[tex]\[ \boxed{184} \][/tex]