Answer :

Sure, let's solve for [tex]\( x \)[/tex] given the function [tex]\( g(x) = 5x + 1 \)[/tex] and [tex]\( g(x) = 41 \)[/tex].

1. Start with the given function:
[tex]\[ g(x) = 5x + 1 \][/tex]
and we know that:
[tex]\[ g(x) = 41 \][/tex]

2. Substitute 41 for [tex]\( g(x) \)[/tex] in the equation:
[tex]\[ 5x + 1 = 41 \][/tex]

3. Next, isolate the term containing [tex]\( x \)[/tex]. To do this, subtract 1 from both sides of the equation:
[tex]\[ 5x + 1 - 1 = 41 - 1 \][/tex]
This simplifies to:
[tex]\[ 5x = 40 \][/tex]

4. Now, to solve for [tex]\( x \)[/tex], divide both sides of the equation by 5:
[tex]\[ x = \frac{40}{5} \][/tex]

5. Simplify the division:
[tex]\[ x = 8 \][/tex]

Therefore, the value of [tex]\( x \)[/tex] is [tex]\( 8 \)[/tex].
set 5x+1 = 41
then solve for x
5x=40
x=8