Answer :
To determine how much energy is required to melt 2 kg of gold, you can use the formula:
[tex]\[ Q = m \cdot L_{\text{fusion}} \][/tex]
where [tex]\( Q \)[/tex] is the energy required, [tex]\( m \)[/tex] is the mass of the substance, and [tex]\( L_{\text{fusion}} \)[/tex] is the latent heat of fusion of the substance.
From the table provided, we can see that the latent heat of fusion for gold ([tex]\( L_{\text{fusion}} \)[/tex]) is [tex]\( 62.8 \, \text{kJ/kg} \)[/tex].
Given:
- Mass of gold, [tex]\( m = 2 \, \text{kg} \)[/tex]
- Latent heat of fusion of gold, [tex]\( L_{\text{fusion}} = 62.8 \, \text{kJ/kg} \)[/tex]
Plug these values into the formula:
[tex]\[ Q = 2 \, \text{kg} \times 62.8 \, \text{kJ/kg} \][/tex]
Multiplying these values gives:
[tex]\[ Q = 125.6 \, \text{kJ} \][/tex]
Therefore, the energy required to melt 2 kg of gold is [tex]\( 125.6 \)[/tex] kJ.
[tex]\[ Q = m \cdot L_{\text{fusion}} \][/tex]
where [tex]\( Q \)[/tex] is the energy required, [tex]\( m \)[/tex] is the mass of the substance, and [tex]\( L_{\text{fusion}} \)[/tex] is the latent heat of fusion of the substance.
From the table provided, we can see that the latent heat of fusion for gold ([tex]\( L_{\text{fusion}} \)[/tex]) is [tex]\( 62.8 \, \text{kJ/kg} \)[/tex].
Given:
- Mass of gold, [tex]\( m = 2 \, \text{kg} \)[/tex]
- Latent heat of fusion of gold, [tex]\( L_{\text{fusion}} = 62.8 \, \text{kJ/kg} \)[/tex]
Plug these values into the formula:
[tex]\[ Q = 2 \, \text{kg} \times 62.8 \, \text{kJ/kg} \][/tex]
Multiplying these values gives:
[tex]\[ Q = 125.6 \, \text{kJ} \][/tex]
Therefore, the energy required to melt 2 kg of gold is [tex]\( 125.6 \)[/tex] kJ.