To solve the division problem [tex]\( 94 \div 9 \)[/tex], follow these steps:
1. Determine how many times 9 can go into the two-digit number 94.
2. Start by examining the first digit of 94, which is 9. Since 9 divided by 9 is 1 (because [tex]\( 9 \times 1 = 9 \)[/tex]), we have:
[tex]\[
9 \div 9 = 1
\][/tex]
3. Write the quotient "1" at the top, above the dividend. Subtract [tex]\( 9 \times 1 = 9 \)[/tex] from 9, which leaves a remainder of 0. Next, bring down the next digit, which is 4.
4. Now, look at the number formed by the remaining digits, which is 4. Determine how many times 9 can go into 4. Since 9 is greater than 4, it goes 0 times into 4. Write the quotient "0" next to the previous quotient.
5. Finally, after writing the quotient as "10", recognize that the remainder from dividing 4 by 9 is 4 itself (since [tex]\( 0 \times 9 + 4 = 4 \)[/tex]).
In conclusion, when dividing 94 by 9, the quotient is 10 and the remainder is 4.
Thus, the result is:
[tex]\[
94 \div 9 = 10 \text{ R } 4
\][/tex]
Or, in another form:
[tex]\[
94 \div 9 = 10 \text{ with a remainder of } 4
\][/tex]
