Let's analyze the given question step-by-step:
1. Identify Event A (The animal is a bird):
- The animals considered as birds in our context are: Penguin, Seagull, and Crow. Hence, [tex]\( A = \{\text{penguin}, \text{seagull}, \text{crow}\} \)[/tex].
2. Identify Event B (The animal can fly):
- The animals that can fly in our context are: Seagull, Crow, Bat, and Mosquito. Hence, [tex]\( B = \{\text{seagull}, \text{crow}, \text{bat}, \text{mosquito}\} \)[/tex].
3. Determine the outcomes that are in both Event A and Event B (A ∩ B):
- We need to find the intersection of sets A and B, which includes animals that are both birds and can fly.
- From [tex]\( A \)[/tex] and [tex]\( B \)[/tex]:
- Penguin: In A but not in B (penguins can't fly).
- Seagull: In both A and B (seagulls can fly and are birds).
- Crow: In both A and B (crows can fly and are birds).
- Bat: In B but not in A (bats can fly but are not birds).
- Mosquito: In B but not in A (mosquitoes can fly but are not birds).
Thus, the outcomes in [tex]\( A \)[/tex] and [tex]\( B \)[/tex] are [tex]\(\{\text{seagull}, \text{crow}\}\)[/tex].
So, the correct answer is:
D. \{seagull, crow\}.
