Earth's gravitational potential energy:
[tex]\[ \text{GPE} = mgh \][/tex]
where:
- [tex]\( g \)[/tex] is the acceleration due to gravity [tex]\( \left(9.8 \, \text{m/s}^2 \right) \)[/tex]
- [tex]\( m \)[/tex] is mass [tex]\( (\text{kg}) \)[/tex]
- [tex]\( h \)[/tex] is height [tex]\( (\text{m}) \)[/tex]

Kinetic energy:
[tex]\[ KE = \frac{1}{2}mv^2 \][/tex]

How would you calculate the gravitational potential energy of a 2 kg bottle of soda falling off of a kitchen table that is 0.76 m tall?

A. [tex]\(\frac{(2)(0.76)}{9.8}\)[/tex]

B. [tex]\(\frac{1}{2}(0.76)(2)^2\)[/tex]

C. [tex]\((2)(0.76)(9.8)\)[/tex]

D. [tex]\(\frac{1}{2}(2)\left(0.76^2\right)\)[/tex]



Answer :

To calculate the gravitational potential energy (GPE) of a 2 kg bottle of soda falling off a kitchen table that is 0.76 m tall, you need to use the formula for gravitational potential energy:

[tex]\[ \text{GPE} = m \cdot g \cdot h \][/tex]

where:
- [tex]\( m \)[/tex] is the mass (in kilograms)
- [tex]\( g \)[/tex] is the acceleration due to gravity (in meters per second squared)
- [tex]\( h \)[/tex] is the height (in meters)

In this problem:
- The mass [tex]\( m \)[/tex] is 2 kg.
- The height [tex]\( h \)[/tex] is 0.76 meters.
- The acceleration due to gravity [tex]\( g \)[/tex] is typically approximated as 9.8 m/s² near the Earth's surface (despite the text's small typographical error in units for gravity).

Substituting these values into the formula gives:

[tex]\[ \text{GPE} = (2 \, \text{kg}) \times (9.8 \, \text{m/s}^2) \times (0.76 \, \text{m}) \][/tex]

Calculating this, you get:

[tex]\[ \text{GPE} = 2 \times 9.8 \times 0.76 \][/tex]

Carefully computing the multiplication:

[tex]\[ 2 \times 9.8 = 19.6 \][/tex]

[tex]\[ 19.6 \times 0.76 = 14.896 \][/tex]

Therefore, the gravitational potential energy (GPE) is 14.896 Joules.

Now, let's match this solution to the correct multiple-choice answer. The correct formula to use here is:

[tex]\[ (2) (0.76) (9.8) \][/tex]

Which corresponds to option C:

[tex]\[ (2)(0.76) 9.8 \][/tex]

Thus, the correct answer is:

C. [tex]\((2)(0.76) 9.8\)[/tex]