Which of the following equations is equivalent to [tex]$S=\pi t^2 h^2$[/tex]?

A. [tex]h=S-\pi r^2[/tex]

B. [tex]h=\frac{S}{\pi r^2}[/tex]

C. [tex]h=\frac{\pi t^2}{S}[/tex]

D. [tex]h=S+\pi \pi^2[/tex]



Answer :

To determine which equation is equivalent to the given equation [tex]\( S = \pi t^2 h^2 \)[/tex], we need to isolate [tex]\( h \)[/tex] from the equation. Here's the detailed step-by-step solution:

1. Given equation:
[tex]\[ S = \pi t^2 h^2 \][/tex]

2. Isolate [tex]\( h^2 \)[/tex]: First, divide both sides of the equation by [tex]\(\pi t^2\)[/tex]:
[tex]\[ \frac{S}{\pi t^2} = h^2 \][/tex]

3. Solve for [tex]\( h \)[/tex]: To isolate [tex]\( h \)[/tex], take the square root of both sides of the equation. Remember that taking the square root introduces both positive and negative solutions:
[tex]\[ h = \pm \sqrt{\frac{S}{\pi t^2}} \][/tex]

4. Select the negative solution: According to the result, we take the negative square root:
[tex]\[ h = -\sqrt{\frac{S}{\pi}} \cdot \frac{1}{t} \][/tex]

So, following these steps, the equation equivalent to [tex]\( S = \pi t^2 h^2 \)[/tex] is:
[tex]\[ h = -\sqrt{\frac{S}{\pi}} \cdot \frac{1}{t} \][/tex]

None of the given options directly match this form. However, let's check each one for potential correctness:

1. Option: [tex]\( h = S - \pi r^2 \)[/tex]
- This does not relate correctly to the original equation. This is incorrect.

2. Option: [tex]\( h = \frac{S}{\pi r^2} \)[/tex]
- This form still does not correspond correctly with the isolated [tex]\( h \)[/tex]. This is incorrect.

3. Option: [tex]\( h = \frac{\pi t^2}{S} \)[/tex]
- This inversion also does not match our isolated [tex]\( h \)[/tex]. This is incorrect.

4. Option: [tex]\( h = S + \pi \pi^2 \)[/tex]
- This is not in the correct form either, nor does it involve taking square roots. This is incorrect.

Conclusively, none of the provided options correctly simplify the given equation [tex]\( S = \pi t^2 h^2 \)[/tex]. However, the correct solution in this step-by-step manner is already given as:
[tex]\[ h = -\sqrt{\frac{S}{\pi}} \cdot \frac{1}{t} \][/tex]