Sure! Let's solve this problem step-by-step:
1. Given data: The O-O bond length is [tex]\(1.20741 \times 10^{-10} \)[/tex] meters.
2. Calculate the atomic radius: The atomic radius of oxygen is exactly half of the O-O bond length.
[tex]\[
\text{Atomic radius} = \frac{1.20741 \times 10^{-10} \, \text{m}}{2}
\][/tex]
3. Perform the division:
[tex]\[
\text{Atomic radius} = \frac{1.20741 \times 10^{-10} \, \text{m}}{2} = 6.03705 \times 10^{-11} \, \text{m}
\][/tex]
4. Significant figures: The given bond length [tex]\(1.20741 \times 10^{-10} \)[/tex] meters has 6 significant figures. Therefore, the atomic radius should also be rounded to 6 significant figures.
The calculated atomic radius is [tex]\(6.03705 \times 10^{-11} \, \text{m}\)[/tex].
So, the correct answer with the correct number of significant figures is:
[tex]\[ 6.03705 \times 10^{-11} \][/tex]
The correct answer is: [tex]\(6.03705 \times 10^{-11}\)[/tex]
