\begin{tabular}{c|c}
[tex]$x$[/tex] & [tex]$f(x)$[/tex] \\
\hline 6 & 11 \\
7 & 13 \\
8 & 15 \\
9 & 17 \\
10 & 19
\end{tabular}

Type of function and nature of change:

Explicit equation:

Recursive equation:



Answer :

Let's analyze the given data points and determine the nature of the function, along with its explicit and recursive equations.

We have the following data points:

[tex]\[ \begin{array}{c|c} x & f(x) \\ \hline 6 & 11 \\ 7 & 13 \\ 8 & 15 \\ 9 & 17 \\ 10 & 19 \\ \end{array} \][/tex]

### Step-by-Step Solution:

1. Determine the differences between consecutive [tex]\( f(x) \)[/tex] values:

Calculate the differences between each consecutive pair of [tex]\( f(x) \)[/tex] values to see if the change is constant.
[tex]\[ \begin{aligned} f(7) - f(6) &= 13 - 11 = 2 \\ f(8) - f(7) &= 15 - 13 = 2 \\ f(9) - f(8) &= 17 - 15 = 2 \\ f(10) - f(9) &= 19 - 17 = 2 \\ \end{aligned} \][/tex]

Since all differences are equal to 2, the function [tex]\( f(x) \)[/tex] shows a constant rate of change.

2. Identify the type of function:

A constant rate of change in the differences indicates that [tex]\( f(x) \)[/tex] is a linear function.

3. Find the explicit equation of the linear function:

The general form of a linear function is:
[tex]\[ f(x) = mx + b \][/tex]
where [tex]\( m \)[/tex] is the slope and [tex]\( b \)[/tex] is the y-intercept.

From the differences, we know that the slope [tex]\( m \)[/tex] is 2.

Now, use one of the points to solve for [tex]\( b \)[/tex]. Using [tex]\( x = 6 \)[/tex] and [tex]\( f(6) = 11 \)[/tex]:
[tex]\[ 11 = 2 \cdot 6 + b \\ 11 = 12 + b \\ b = 11 - 12 \\ b = -1 \][/tex]

Therefore, the explicit equation is:
[tex]\[ f(x) = 2x - 1 \][/tex]

4. Find the recursive equation:

The recursive form of a linear function can be expressed as:
[tex]\[ f(x + 1) = f(x) + m \][/tex]
Given [tex]\( m = 2 \)[/tex], the recursive equation is:
[tex]\[ f(x + 1) = f(x) + 2 \][/tex]

### Summary:

- Type of function and nature of change:

The function is linear with a constant rate of change of 2.

- Explicit equation:

[tex]\[ f(x) = 2x - 1 \][/tex]

- Recursive equation:

[tex]\[ f(x + 1) = f(x) + 2 \][/tex]