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A 400 kg object is sitting at rest at the top of a hill that is 30.0m high and 80.0m long measured along the hill . If there is no friction ,how fast will the object be going at the bottom of the hill?



Answer :

theater=sin^-1(30/80)
theater=22
F=400gsin22=150N
F=ma
150=400a
a=0.375ms^-2
v^2-u^2=2as
v^2-0=2x0.375x80
v=7.75ms^-1

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