You use a 1200-watt hair dryer for 10 minutes each day. a. How many minutes do you use the hair dryer in a month? (Assume there are 30 days in the month.) b. How many hours do you use the hair dryer in a month? c. What is the power of the hair dryer in kilowatts? d. How many kilowatt-hours of electricity does the hair dryer use in a month? e. If your town charges $0.15/kWh, what is the cost to use the hair dryer for a month?



Answer :

300 minuts
5 hours
1.2 killowatt
6 killowatt hour
6*0.15=0.9
$0.9

Data;

  • Power = 1200W
  • Time/day = 10 mins

Power

The is the rate of energy used to time. It is the measure of expedience of energy.

a). How many minutes is the dryer used in a month.

Assuming there 30 days in a month;

[tex]1 day = 10 mins\\30 days = x mins\\x = 30 * 10 \\x = 300 mins[/tex]

This shows that the dryer is used 300 minutes in a month.

b). How many hours is the dryer used in a month.

To solve this problem, we simply need to convert the value of (a) from minutes to hours.

[tex]1hr = 60 mins\\y hr = 300 mins\\y = \frac{300}{60} \\y = 5 hours[/tex]

The dryer was used for a total of 5 hours in a month.

c). The power of the dryer in  kilowatt.

To convert the power in watt to kilowatt, we divide by 1000.

[tex]P = 1200W\\P = \frac{1200}{1000} \\P = 1.2kw[/tex]

The power in kilowatt is 1.2kw

d). How many kilowatt/hr of electricity used in a month.

[tex]1.2 * 5 = 6kw/h[/tex]

The dryer consumes 6kw/h in a month.

e). If the town charges $0.15/kwh, the cost in a month

[tex]\$0.15 = 1hr\\x= 6hr\\x = 6 * 0.15\\x = 0.9[/tex]

The cost of the dryer in a month is $0.9.

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