You haven't mentioned whether the resistors are in series or in parallel.
It's kind of important, and the answers are different.
If they're in series:
The total resistance is (R1 + R2) = (7 + 15) = 22 ohms
Current = (voltage) / (total resistance) = (220) / (22) = 10 Amperes
If they're in parallel:
The total resistance is (R1 · R2) / (R1 + R2) = (7 · 15) / (7 + 15) = 105/22 ohms
Current = voltage / total resistance = 220 · 22 / 105 = 46.1 Amperes.
The poor power supply could probably not deliver 46.1A for very long,
so I'm guessing that the resistors are in series, and the current is 10A.
