Answer :
You haven't mentioned whether the resistors are in series or in parallel.
It's kind of important, and the answers are different.
If they're in series:
The total resistance is (R1 + R2) = (7 + 15) = 22 ohms
Current = (voltage) / (total resistance) = (220) / (22) = 10 Amperes
If they're in parallel:
The total resistance is (R1 · R2) / (R1 + R2) = (7 · 15) / (7 + 15) = 105/22 ohms
Current = voltage / total resistance = 220 · 22 / 105 = 46.1 Amperes.
The poor power supply could probably not deliver 46.1A for very long,
so I'm guessing that the resistors are in series, and the current is 10A.
It's kind of important, and the answers are different.
If they're in series:
The total resistance is (R1 + R2) = (7 + 15) = 22 ohms
Current = (voltage) / (total resistance) = (220) / (22) = 10 Amperes
If they're in parallel:
The total resistance is (R1 · R2) / (R1 + R2) = (7 · 15) / (7 + 15) = 105/22 ohms
Current = voltage / total resistance = 220 · 22 / 105 = 46.1 Amperes.
The poor power supply could probably not deliver 46.1A for very long,
so I'm guessing that the resistors are in series, and the current is 10A.
