Answer :
[tex]r=6in\\\\H=8in\\\\A=\pi rl\\\\Pythagoras\ theorem:\\\\r^2+H^2=l^2\\\\l^2=6^2+8^2\\\\l^2=36+64\\\\l^2=100\\\\l=\sqrt{100}\\\\l=10\ (in)[/tex]
[tex]A=\pi\cdot6\cdot10=60\pi\ (in^2)[/tex]
[tex]A=\pi\cdot6\cdot10=60\pi\ (in^2)[/tex]
