Answer :

kate200468
[tex]log_3( \frac{1}{9} )= \frac{x}{9} \\\\log_33^{-2}= \frac{x}{9} \\\\-2=\frac{x}{9} \ /\cdot9\\\\-18=x\\\\x=-18[/tex]
Ryan2
[tex]log_3(\frac{1}{9})=\frac{x}{9}\\ \\ log_33^{-2}=\frac{x}{9}\\ \\ 3^{\frac{x}{9}}=3^{-2}\\ \\ \frac{x}{9}=-2\\ \\ \boxed{x=-18}[/tex]