Answer :
[tex]x-\frac{4}{5}=\frac{6}{7}[/tex]
Pass the [tex]\frac{4}{5}[/tex] but change the signal
[tex]x=\frac{6}{7}+\frac{4}{5}[/tex]
now we have to make the minimum common multiple of 7 and 5, this number will be 35 therefore
[tex]x=\frac{6*5}{35}+\frac{4*7}{35}[/tex]
[tex]x=\frac{30}{35}+\frac{28}{35}[/tex]
now we can add both
[tex]x=\frac{30}{35}+\frac{28}{35}[/tex]
[tex]x=\frac{30+28}{35}[/tex]
[tex]\boxed{\boxed{x=\frac{58}{35}}}[/tex]
Pass the [tex]\frac{4}{5}[/tex] but change the signal
[tex]x=\frac{6}{7}+\frac{4}{5}[/tex]
now we have to make the minimum common multiple of 7 and 5, this number will be 35 therefore
[tex]x=\frac{6*5}{35}+\frac{4*7}{35}[/tex]
[tex]x=\frac{30}{35}+\frac{28}{35}[/tex]
now we can add both
[tex]x=\frac{30}{35}+\frac{28}{35}[/tex]
[tex]x=\frac{30+28}{35}[/tex]
[tex]\boxed{\boxed{x=\frac{58}{35}}}[/tex]
