A soccer ball is placed 12 feet away from a goal post that measures 8ft high. You kick the ball and it hits the crossbar at the top the goal. What was the angle of elevation of you kick?

Question

Answered

Answer :

Ryan2 Ryan2 · Answer 1 · 2014-07-11T20:45:00-04:00

[tex]tg(\theta)=\frac{8}{12}\\ \\ tg(\theta)=0.666... \rightarrow \theta\approx35^o[/tex]

Answer Link

AFOKE88 AFOKE88 · Answer 2 · 2022-02-18T06:00:27-05:00

The angle of elevation at which he kicks the ball is; 36.89°

We are told that the ball is 12 ft away and so we will consider it to be the horizontal distance.

The post is 8 ft high and so we will consider it to be the vertical distance.

Thus, we can use trigonometric ratio to find the angle of elevation. Thus;

tan θ = 8/12

θ = tan⁻¹0.75

θ = 36.89°

In conclusion the angle of elevation at which he kicks the ball is 36.89°

Read more about Angle of elevation at; https://brainly.com/question/19594654