Answer :

If you wanted to calculate it, there it is:
[tex](\frac{8}{9})^2 (-81)+\frac{\frac{3}{5}}{\frac{-9}{10}} = \frac{64}{81}*(-81)+\frac{3}{5}*\frac{10}{-9} = -64+\frac{-2}{3}= \\ =-64-\frac{2}{3}=\frac{-192-2}{3}=\frac{-194}{3}[/tex]

Answer: -64.0066666667

(((8\9)squared)*(-81))+(((3\5)\(-9))\10)

Step-by-step explanation:

Other Questions