Answer :
5x² + 5x + nothing
Ax² + Bx + C
A = 5
B = 5
C = 0
Quadratic formula:
x = (1/2A) times [ -B plus and minus √(B²-4AC) ]
B² - 4AC = 25 - 4(5)(0) = 25
-B plus and minus √25 = -5 plus and minus 5 = -10 and zero.
(1/2A) times (-10 and zero) = (1/10) times (-10 and zero) = -1 and zero
x = 1
and
x = 0
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What is that '6' doing in there ?
Where does it belong ?
Did you copy the problem correctly ?
Ax² + Bx + C
A = 5
B = 5
C = 0
Quadratic formula:
x = (1/2A) times [ -B plus and minus √(B²-4AC) ]
B² - 4AC = 25 - 4(5)(0) = 25
-B plus and minus √25 = -5 plus and minus 5 = -10 and zero.
(1/2A) times (-10 and zero) = (1/10) times (-10 and zero) = -1 and zero
x = 1
and
x = 0
===============================
What is that '6' doing in there ?
Where does it belong ?
Did you copy the problem correctly ?
