jessicapuiting jessicapuiting
  • 08-06-2014
  • Mathematics
Answered

Someone please help me? I don't know how to solve these :/

Someone please help me I dont know how to solve these class=


Answer :

iloveonedirection
iloveonedirection iloveonedirection
  • 08-06-2014
[tex]2x^2 - x - 6 = 0[/tex]

[tex](2x - 3) (x + 2) = 0[/tex]

[tex]2x - 3 = 0[/tex]

[tex]2x = 3[/tex]

[tex]x = \frac{3}{2} [/tex]

[tex]x + 2 = 0[/tex]

[tex]x = -2[/tex]

[tex]x = \frac{3}{2} , 2[/tex]
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konrad509
konrad509 konrad509
  • 08-06-2014
[tex]2x^2-x-6=0\\ 2x^2-4x+3x-6=0\\ 2x(x-2)+3(x-2)=0\\ (2x+3)(x-2)=0\\ x=-\frac{3}{2} \vee x=2[/tex]
Answer Link

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