Answer :

AL2006
I think this is shown in the fine print on the second sheet . . .


The question starts out by saying that the scale uses two 3V cells in series.
That makes the total battery voltage 6 volts.

0.12 milliamperes = 0.00012 Amperes.

Resistance = (voltage) / (current in Amperes).

Resistance = 6 / 0.00012 = 50,000 Ω






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