Answer :
Reduced Equation:
[tex](x-x_o)^2+(y-y_o)=r^2\\ \\ (x+4)^2+(y-3)^2=16\\ \\ x^2+8x+16+y^2-6y+9-16=0\\ \\ \boxed{x^2+y^2+8x-6y+9=0}[/tex]
[tex](x-x_o)^2+(y-y_o)=r^2\\ \\ (x+4)^2+(y-3)^2=16\\ \\ x^2+8x+16+y^2-6y+9-16=0\\ \\ \boxed{x^2+y^2+8x-6y+9=0}[/tex]
I'm going to assume that you're asking for the equation of that circle.
It's
(x + 4)² + (y - 3)² = 16
It's
(x + 4)² + (y - 3)² = 16
