Answer :

[tex]\left\{\begin{array}{ccc}x+y=251\\y=x+41\end{array}\right\\\\substitute:\\\\x+x+41=251\\2x+41=251\ \ \ \ /-41\\2x=210\ \ \ /:2\\x=105\\\\y=105+41=146\\\\Answer:105\ and\ 146.[/tex]

146 dan 105

Further explanation

Given:

Two numbers add to 251 and the second is 41 bigger than the first.

Question:

What are the two numbers?

The Process:

Let the first number we call x, and the second number is y.

Two numbers add to 251, We arrange it as Equation-1:

[tex]\boxed{ \ x + y = 251 \ }[/tex]

The second is 41 bigger than the first. We arrange it as Equation-2:

[tex]\boxed{ \ x = y + 41 \ } \ or \ \boxed{ \ x - y = 41 \ }[/tex]

Let us solve the two equations above by eliminating the same variable. With the addition process, it appears that the variable y will be eliminated.

x + y = 251

x - y = 41

-------------- ( + )

2x = 292

Divide by two on both sides.

x = 146

The final step is to determine the variable y with the substitution of the value x into one of the two equations above. We choose Equation-1.

x = 146 → 146 + y = 251

y = 251 - 146

y = 105.

Thus, the two numbers are 146 and 105.

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