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A large passenger aircraft accelerates down the runway for a distance of 3300 m before leaving the ground. It then climbs at a steady 6.3 degree angle.After the plane has traveled 3200 m along this new trajectory, how high is it?



Answer :

[tex]sin6.3^o=\frac{h}{3200}\\\\sin6.3^o\approx0.1097\\\\\frac{h}{3200}=0.1097\ \ \ \ /\cdot3200\\\\h\approx351\ (m)\\\\Answer:351m[/tex]
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