Answer :
A. K(s) + F2(g) → KF2(s)
B. K(s) + F(g) → KF(s)
C. K2(g) + F2(g) → 2 KF(s)
D. 2 K(s) + F2(g) → 2 KF(s)
it exists as a pale yellow diatomic gas at standard conditions!!
B. K(s) + F(g) → KF(s)
C. K2(g) + F2(g) → 2 KF(s)
D. 2 K(s) + F2(g) → 2 KF(s)
it exists as a pale yellow diatomic gas at standard conditions!!