Answer :

pH = -log[H⁺]

Ca(OH)₂ <---> Ca²⁺ + 2OH⁻

Concentration = 10⁻² mol/l = 0,01 mol/l

pOH = -log[OH⁻]
pOH = -log(0,01) = 2
pH + pOH = 14
pH + 2 = 14
pH = 14 - 2
pH = 12

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