MieshaHawke476 MieshaHawke476
  • 14-07-2014
  • Mathematics
Answered

sinxtanx=secx-cosx Please help me solve it



Answer :

Ryan2
Ryan2 Ryan2
  • 14-07-2014
[tex]sinx.tanx=secx-cosx\\ \\ sinx.\frac{sinx}{cosx}=\frac{1}{cosx}-cosx\\ \\ \frac{sin^2x}{cosx}=\frac{1-cos^2x}{cosx}\\ \\ \frac{sin^2x}{cosx}=\frac{sin^2x}{cosx}[/tex]
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