Answer :
Pretty slow that train ;)
t=s/v
v=12 km/h=10/3 m/s
s=250+50=300 m
t=300/(10/3)
t=300*3/10
t=30*3
t=90 s=1.5 min
t=s/v
v=12 km/h=10/3 m/s
s=250+50=300 m
t=300/(10/3)
t=300*3/10
t=30*3
t=90 s=1.5 min
From the instant when the nose of the locomotive reaches the beginning of the
bridge, it has to travel the whole 250m to get to the other end of the bridge, and
then it has to travel another 50m to get the rest of the train off the bridge. So it
has to travel 300m to get everything it's pulling across the bridge.
Time = distance/speed = 300m / (12,000 m/hr) = 0.025 hour = 1 minute 30 sec
bridge, it has to travel the whole 250m to get to the other end of the bridge, and
then it has to travel another 50m to get the rest of the train off the bridge. So it
has to travel 300m to get everything it's pulling across the bridge.
Time = distance/speed = 300m / (12,000 m/hr) = 0.025 hour = 1 minute 30 sec
