Answer :
[tex]4x^2+16x=0[/tex]
[tex] \frac{4x^2+16x}{4} =\frac{0}{4} [/tex]
[tex]x^2+4x=0[/tex]
[tex]x(x+4)=0[/tex]
[tex]x=0[/tex]
[tex]x+4=0[/tex]
[tex]x+4-4=0-4[/tex]
[tex]x=-4[/tex]
[tex]x=-4,0[/tex]
[tex] \frac{4x^2+16x}{4} =\frac{0}{4} [/tex]
[tex]x^2+4x=0[/tex]
[tex]x(x+4)=0[/tex]
[tex]x=0[/tex]
[tex]x+4=0[/tex]
[tex]x+4-4=0-4[/tex]
[tex]x=-4[/tex]
[tex]x=-4,0[/tex]
Divide each side of the equation by 4 :
x² + 4x = 0
Factor the left side:
x (x + 4) = 0
This equation is true if x=0 or if x=-4 , so those are the two solutions.
x² + 4x = 0
Factor the left side:
x (x + 4) = 0
This equation is true if x=0 or if x=-4 , so those are the two solutions.
