Answer :
The equation is [tex]-0.25x^2-x+2=0[/tex]
The coordinates are [tex](\frac{-b}{2a};\frac{-\Delta}{4a})[/tex]
[tex]\Delta=b^2-4ac=1+2=3[/tex]
The coordinates, thus, are [tex](\frac{1}{-0.5};\frac{-1}{-1})=(-2;1)[/tex]
The coordinates are [tex](\frac{-b}{2a};\frac{-\Delta}{4a})[/tex]
[tex]\Delta=b^2-4ac=1+2=3[/tex]
The coordinates, thus, are [tex](\frac{1}{-0.5};\frac{-1}{-1})=(-2;1)[/tex]
Answer:
Option B is right.
Step-by-step explanation:
given is an equation of a parabola
[tex]-0.25x^2 =y-2\\y=-0.25x^2 +2[/tex]
[tex]-x^2 =4y-8[/tex]
Vertex is (0,2)
It is open down.
Axis of symmetry is x=0 or y axis
Hence focus will lie on axis of symmetry ie y axis.
THe parabola has -4a = -4
Hence a = 1
SO focus will lie inside the parabola on axis of symmetry with a distance of a units from the vertex.
i.e. focus would equal = (0,2-1) = (0,1)
Option B is right
