Answer :

[tex]D:x-1\geq0\\ D:x\geq1\\\\[/tex]

[tex]\hbox{ range of } \sqrt {x-1} \hbox{ is } \langle0,\infty)\\ \hbox{ range of } -\frac{3}{4}\sqrt {x-1} \hbox{ is } \langle-\frac{3}{4}\cdot0,-\frac{3}{4}\cdot\infty)=(-\infty,0\rangle\\ \hbox{ range of } -\frac{3}{4}\sqrt {x-1}+4 \hbox{ is } (-\infty+4,0+4\rangle=(-\infty,4\rangle\\ [/tex]

Other Questions