Answer :

MattD
[tex]ax^2+bx+c=0\\[/tex]
[tex]3x^2-7x+9=0[/tex]
a=3 b=-7 c=9
[tex]\Delta=b^2-4ac=(-7)^2-4*3*9=49-108=-59[/tex]
[tex]\Delta<0[/tex]
If the delta is less than zero and if no polynomial real roots
Lilith
[tex]3x^2 - 7x + 9 = 0 \\ \\a=3, \ \ b=-7, \ \ c= 9 \\ \\ \Delta =b^2-4ac = 7^2 -4\cdot 3 \cdot 9 = 49-108= -59 \\ \\ If \ \Delta <0, \ then \ roots \ are \ imaginary \ (non-real)[/tex]


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