Answer :
p - pressure [Pa]
Fn - pressure force [N]
S - surface area [m²]
S = 0.19m*0.095=0.01805 [m²] (the two largest values of bricks)
[tex]p=\frac{F_n}{S}=\frac{25N}{0.01805m^2}=1385[Pa][/tex]
Fn - pressure force [N]
S - surface area [m²]
S = 0.19m*0.095=0.01805 [m²] (the two largest values of bricks)
[tex]p=\frac{F_n}{S}=\frac{25N}{0.01805m^2}=1385[Pa][/tex]
Answer:
The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.
Explanation:
Given that,
Weight of brick = 25 N
The dimensions of a brick are 0.19 m × 0.07 m × 0.095 m.
The pressure of the brick exert on the ground if it is resting on its largest face.
So, The area of largest face of brick is
[tex]A = 0.19\times 0.095[/tex]
[tex]A= 0.01805\ m^2[/tex]
The pressure of the brick on the ground is
The pressure is the force upon area.
The formula of pressure is
[tex]P =\dfrac{F}{A}[/tex]
[tex]P=\dfrac{25}{0.01805}[/tex]
[tex]P = 1385.04\ Pa[/tex]
Hence, The pressure of the brick exert on the ground if it is resting on its largest face is 1385.04 Pa.
