Answer :
1 astronomical unit 1 AU = 1.4960 * 10^11 meters
it is the average distance between earth and sun
mercury to sun distance is = 46,000,000 * 1000 meters
= 4.6 * 10^9 meters = 4.6 * 10^9 / 1.4960 * 10^11 AU
= 3.0.74 / 100 = 0.0374 AU
it is the average distance between earth and sun
mercury to sun distance is = 46,000,000 * 1000 meters
= 4.6 * 10^9 meters = 4.6 * 10^9 / 1.4960 * 10^11 AU
= 3.0.74 / 100 = 0.0374 AU
Explanation :
Astronomical unit is the unit to find the average distance between the earth and the sun.
[tex]1\ AU=1.496\times 10^8\ Km[/tex]
So, [tex]1\ Km=\dfrac{1}{1.496\times 10^8}\ AU[/tex]
46 million kilometers means, [tex]46\times 10^6\ Km[/tex]
[tex]46\times 10^6\ Km=\dfrac{46\times 10^6}{1.496\times 10^8}[/tex]
[tex]46\ million\ Km=0.3074\ AU[/tex]
Hence, this is the required solution.