Answer :
[tex]w-the\ width\\l=w+5-the\ length\\\\\\The\ perimeter\ of\ rectangle:P=58cm\\\\P=2w+2l\\\\2w+2(w+5)=58\\2w+2w+10=58\\4w+10=58\ \ \ \ |subtract\ 10\ from\ both\ sides\\4w=48\ \ \ \ \ |divide\ both\ sides\ by\ 4\\w=12\ (cm)\\\\l=12+5=17\ (cm)\\\\Answer:The\ dimensions\ of\ the\ rectangle:17cm\times12cm[/tex]