Answer :

[tex]f(x)=(x+10)^2\\\\\Downarrow T_{\vec{a}=[12; 0]-translation\ 12\ units\ to\ the\ right}\\\\g(x)=(x+10-12)^2=(x-2)^2[/tex]
g ( x ) = ( x + 10 -12 )²
         =  ( x- 2 )² Answer