Answer :
[tex]\frac{1}{14}(3x-2)=\frac{x+10}{10}\ \ \ \ \ |multiply\ both\ sides\ by\ 140\\\\10(3x-2)=14(x+10)\\\\30x-20=14x+140\\\\30x-14x=140+20\\\\16x=160\\\\x=160:16\\\\\boxed{x=10}[/tex]
[tex] \frac{1}{14}(3x-2)=\frac{x+10}{10} \ \ / \cdot 140\\\\140\cdot \frac{1}{14}(3x-2)=140\cdot\frac{x+10}{10}\\ \\10(3x-2)=14(x+10)\\\\30x-20 =14x+140\\\\30x-14x=140+20\\ \\16x=160 \ \ /:16\\ \\x=10[/tex]
