Answer :
[tex]\frac{3}{2y}=\frac{16}{y+2}\ \ \ \ \ \ |cross\ multiply\\\\16\times2y=3(y+2)\\\\32y=3y+6\ \ \ \ \ |subtract\ 3y\ from\ both\ sides\\\\29y=6\ \ \ \ \ \ \ |divide\ both\ sides\ by\ 29\\\\\boxed{y=\frac{6}{29}}[/tex]
