A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coach bought 6 more hamburgers and 2 more fries for $16.60. Find the cost of each.

Basically this is a systems of equations question. We set up two equations, X is hamburgers Y is fries

8x + 5y = 24
6x + 2y = 16.60

then you solve for each to get your answer.

Answer Link

Alleei Alleei · Answer 2 · 2020-01-08T06:49:43-05:00

Answer : The cost of hamburgers and fries is, $2.5 and $0.8

Step-by-step explanation :

Let the cost of hamburgers be, x and the cost of fries be, y.

Thus the two equation will be:

[tex]8x+5y=24[/tex] ...........(1)

[tex]6x+2y=16.60[/tex] .............(2)

Using substitution method:

From equation 1 we have to determine the value of 'y'.

[tex]8x+5y=24[/tex]

[tex]5y=24-8x[/tex]

[tex]y=\frac{24-8x}{5}[/tex] ........(3)

Now put equation 3 in 2, we get:

[tex]6x+2y=16.60[/tex]

[tex]6x+2\times (\frac{24-8x}{5})=16.60[/tex]

[tex]6x+(\frac{48-16x}{5})=16.60[/tex]

[tex]\frac{30x+48-16x}{5}=16.60[/tex]

[tex]30x+48-16x=83[/tex]

[tex]14x=35[/tex]

[tex]x=2.5[/tex]

Now put the value of x in equation 3, we get:

[tex]y=\frac{24-8x}{5}[/tex]

[tex]y=\frac{24-8\times 2.5}{5}[/tex]

[tex]y=\frac{24-20}{5}[/tex]

[tex]y=\frac{4}{5}[/tex]

[tex]y=0.8[/tex]

Thus, the cost of hamburgers and fries is, $2.5 and $0.8