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The height (in meters) of a projectile shot vertically upward from a point 2m above ground level with an initial velocity of 24.5m/s is h=2+24.5t-4.9t^2 after t seconds. When does the projectile hit the ground? With what velocity does it hit the ground?



Answer :

For the moment one hits the ground, you set h=0 and solve for t.
To find out the speed, you must find out [tex]v=24.5-9.8t[/tex]

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