Answer :
N
N+2
N+4
N+6
That would be the answer for the first sequence.
Your second question--the integers would be 11,13,15, and 17
N+2
N+4
N+6
That would be the answer for the first sequence.
Your second question--the integers would be 11,13,15, and 17
Every second integer is odd. (The ones in between them are even.)
If you promise that 'n' is odd, then the next odd ones
are (n+2), (n+4), and (n+6) .
We need to add them all up:
n + (n+2) + (n+4) + (n+6) = 4n + 12
Now you're telling me that the sum is 56. Knowing that, I can
figure out what 'n' is, and once I know 'n', I can fiugure out all
four of the numbers.
4n + 12 = 56
Subtract 12 from each side: 4n = 44
Divide each side by 4 : n = 11
The four consecutive odd integers are:
n . . . . . 11
n+2 . . . 13
n+4 . . . 15
n+6 . . . 17 .
Check the answer:
Add up (11 + 13 + 15 + 17) = 56 yay !