Answer :

[tex]12|2\\.\ 6|2\\.\ 3|3\\.\ 1|\\12=2\cdot2\cdot3\\\\28|2\\14|2\\.\ 7|7\\.\ 1|\\28=2\cdot2\cdot7\\\\\frac{12}{28}=\frac{2\cdot2\cdot3}{2\cdot2\cdot7}=\boxed{\frac{3}{7}}[/tex]

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