How long would it take 2.0x10^20 electrons to pass through a point in a conductor if the current was 10.0A?



Answer :

AL2006

1 coulomb of electric charge is carried by  6.25 x 10^18 electrons

1 Ampere = 1 coulomb per second
10 A = 10 coulombs per second

(2.0 x 10^20 electrons) x (coul / 6.25 x 10^18 electrons) / (10 coul/sec) =

         (2.0 x 10^20) / (6.25 x 10^18 x 10)    sec  =  3.2 seconds


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