Answered

If ƒ(x) varies directly with x and ƒ(x) = 32 when x = -8, then what is ƒ(x) when x = 4?
A. -12
B. -1
C. -16
D. -8



Answer :

[tex]f(x)=kx\\ 32=-8k\\ k=-4\\ f(x)=-4x\\\\ f(4)=-4\cdot4=-16[/tex]

Other Questions