Answer :

naǫ
[tex]4x+2y=12 \\ \underline{-4x+5y=-5} \\ 2y+5y=12-5 \\ 7y=7 \\ y=\frac{7}{7} \\ y=1 \\ \\ 4x+2y=12 \\ 4x+2 \times 1=12 \\ 4x+2=12 \\ 4x=12-2 \\ 4x=10 \\ x=\frac{10}{4} \\ x=\frac{5}{2} \\ x=2 \frac{1}{2} \\ \\ \boxed{(x,y)=(2 \frac{1}{2}, 1)}[/tex]
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