Answer :
[tex]4x+2y=12 \\
\underline{-4x+5y=-5} \\
2y+5y=12-5 \\
7y=7 \\
y=\frac{7}{7} \\
y=1 \\ \\
4x+2y=12 \\
4x+2 \times 1=12 \\
4x+2=12 \\
4x=12-2 \\
4x=10 \\
x=\frac{10}{4} \\
x=\frac{5}{2} \\
x=2 \frac{1}{2} \\ \\
\boxed{(x,y)=(2 \frac{1}{2}, 1)}[/tex]