Answer :
[tex]16x^2=9[/tex] becomes [tex]16x^2-9=0[/tex] ([tex]+0x[/tex] is implied)
To solve a quadratic like this we need to find two numbers that multiply to equal ac and add up to b. In this case, two numbers that multiply to equal -144 and add to equal 0. These two numbers are 12 and -12. Factor using these numbers.
[tex](x+12)(x-12)=0[/tex]
And if you ever need to find x you would just find any value that would cause one of the two to equal 0. Since 0 times anything is still 0, this would work. These values would be 12 and -12. (12-12 = 0, -12+12 = 0)
To solve a quadratic like this we need to find two numbers that multiply to equal ac and add up to b. In this case, two numbers that multiply to equal -144 and add to equal 0. These two numbers are 12 and -12. Factor using these numbers.
[tex](x+12)(x-12)=0[/tex]
And if you ever need to find x you would just find any value that would cause one of the two to equal 0. Since 0 times anything is still 0, this would work. These values would be 12 and -12. (12-12 = 0, -12+12 = 0)
16x² = 9
16x² - 9 = 0
16x² + 0x - 9 = 0
x = 0 +/- √(0² - 4(16)(-9))
2(16)
x = 0 +/- √(0 + 576)
32
x = 0 +/- √(576)
32
x = 0 +/- 24
32
x = 0 + 0.75
x = 0 + 0.75 x = 0 - 0.75
x = 0.75 x = -0.75
16x² - 9 = 0
16x² + 0x - 9 = 0
x = 0 +/- √(0² - 4(16)(-9))
2(16)
x = 0 +/- √(0 + 576)
32
x = 0 +/- √(576)
32
x = 0 +/- 24
32
x = 0 + 0.75
x = 0 + 0.75 x = 0 - 0.75
x = 0.75 x = -0.75
