retakk
retakk
07-04-2015
Mathematics
Answered
2x-8/x^2
what is the range of this function ?
Answer :
Hippalectryon
Hippalectryon
09-04-2015
The function is continuous for [tex]x>0[/tex]. It goes to [tex]-\infty[/tex] when [tex]x\to0[/tex] and it goes to [tex]+\infty[/tex] when [tex]x\to+\infty[/tex] hence its range is [tex]\Bbb{R}=(-\infty,+\infty)[/tex]
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