Answer :
[tex]81x^4-1=\\
(9x^2)^2-1^2=\\
(9x^2+1)(9x^2-1)=\\
(9x^2+1)((3x)^2-1^2)=\\
(9x^2+1)(3x+1)(3x-1)[/tex]
Using this: a²-b²=(a+b)(a-b)
81x^4-1=
(9x²)²-1=
(9x²-1)(9x²+1)= (in the bold half we use the formula again)
(3x+1)(3x-1)(9x²+1)
So the answer is D