Answer :
y - y1 = m(x - x1)
Where 'y1' is the y-value of the point, 'x1' is the x-value of the point, and 'm' is the slope.
So in this case:
y1 = -8
x1 = 6
m = -2
Plug them in:
y - (-8) = -2(x - 6)
or
y + 8 = -2(x - 6)
Where 'y1' is the y-value of the point, 'x1' is the x-value of the point, and 'm' is the slope.
So in this case:
y1 = -8
x1 = 6
m = -2
Plug them in:
y - (-8) = -2(x - 6)
or
y + 8 = -2(x - 6)
Point slope form is:
[tex]\sf {y - y_1 = m(x - x_1)}[/tex]
Where [tex]\sf{(x_1,y_1)}[/tex] is the point and [tex]\sf{m}[/tex] is the slope.
So from your question:
[tex]\sf{ x_1 = 6}[/tex]
[tex]\sf{y_1 = -8}[/tex]
[tex]\sf{m = -2}[/tex]
Plug them into the equation for point slope form:
[tex]\sf {y - y_1 = m(x - x_1)}[/tex]
Becomes when you plug it in:
[tex]\sf{y-(-8) = -2(x - 6)}[/tex]
And when you subtract a negative that becomes addition so:
[tex]\sf{y+ 8 = -2(x - 6)}[/tex]
And that would correlate to answer choice [tex]\sf{\boxed{B}}[/tex]
[tex]\sf {y - y_1 = m(x - x_1)}[/tex]
Where [tex]\sf{(x_1,y_1)}[/tex] is the point and [tex]\sf{m}[/tex] is the slope.
So from your question:
[tex]\sf{ x_1 = 6}[/tex]
[tex]\sf{y_1 = -8}[/tex]
[tex]\sf{m = -2}[/tex]
Plug them into the equation for point slope form:
[tex]\sf {y - y_1 = m(x - x_1)}[/tex]
Becomes when you plug it in:
[tex]\sf{y-(-8) = -2(x - 6)}[/tex]
And when you subtract a negative that becomes addition so:
[tex]\sf{y+ 8 = -2(x - 6)}[/tex]
And that would correlate to answer choice [tex]\sf{\boxed{B}}[/tex]